document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827271>Question 827271</A>: <I><SPAN STYLE=\"word-break: break-all;\">  a streamer,going downstream in a river, covers the distance between 2 towns in 15 hrs. coming backbupstream, it covers this distance in 20 hrs. the speed of the water is 3 km/hr. find the distance between two towns. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498635 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set x = speed without current<BR>\n" );
document.write( "set d = distance<BR>\n" );
document.write( "Going downstream<BR>\n" );
document.write( " rate * time = distance\r<BR>\n" );
document.write( "\n" );
document.write( " (x+3)15 = d so 15x + 45 = d<BR>\n" );
document.write( " (x-3)20 = d, 20x - 60 = d<BR>\n" );
document.write( "Since 15x + 45 = d and 20x - 60 = d<BR>\n" );
document.write( " 15x + 45 = 20x - 60<BR>\n" );
document.write( "subtract 15x from each side<BR>\n" );
document.write( "  45 = 5x - 60<BR>\n" );
document.write( "add 60 to each side<BR>\n" );
document.write( " 105 = 5x<BR>\n" );
document.write( "divide 5 by each side<BR>\n" );
document.write( "  21 = x<BR>\n" );
document.write( "substitute 21 for x in (x+3)15 = d<BR>\n" );
document.write( " (21+3)(15) = d<BR>\n" );
document.write( " (24)(15) = d<BR>\n" );
document.write( " d = 360<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );