document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827286>Question 827286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have two different solutions of sulfuric acid, one with 75% acid and one with 45% acid. If I want to end up with 250ml of 50% acid solution, how much of each solution do I need to use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498587 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have two different solutions of sulfuric acid, one with 75% acid and one with 45% acid. If I want to end up with 250ml of 50% acid solution, how much of each solution do I need to use?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.75x + 0.45(250-x) = 0.50*250<BR>\n" );
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document.write( "75x + 45*250 - 45x = 50*250<BR>\n" );
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document.write( "30x = 5*250<BR>\n" );
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document.write( "x = 41 2/3 ml (amt. of 75% solution needed)<BR>\n" );
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document.write( "250-41 2/3) = 208 1/3 ml (amt. of 45% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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