document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827227>Question 827227</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Trisha needs 41/2 yards of fabric to do a project. If she already has 2/3 of a yard of fabric, what is the minimum amount of fabric she must buy to be able to complete her project? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498563 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> She will need at least ( 4 1/2 - 2/3)\r<BR>\n" );
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document.write( "Since 2/3 is greater than 1/2<BR>\n" );
document.write( "rewrite 4 1/2 as 3 3/2.<BR>\n" );
document.write( "We can do this because 4 1/2 = 3 + 1 + 1/2 = 3 + 1 1/2 = 3 + 3/2 = 3 3/2<BR>\n" );
document.write( "( 4 1/2 - 2/3 ) is the same as<BR>\n" );
document.write( "( 3 3/2 - 2/3 )<BR>\n" );
document.write( "using a common denominator of 6<BR>\n" );
document.write( "( 3 9/6 - 4/6 )<BR>\n" );
document.write( "( 3 5/6 )<BR>\n" );
document.write( "She needs at least 3 5/6 . She might need more if she cannot cut the necessary<BR>\n" );
document.write( "parts from the two pieces ( 3 5/6 and 2/3 ). </SPAN>\n" );
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