document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=827167>Question 827167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the amount accumulated on $500 invested at 8.5% for 3 years compounded semi-annually<BR>\n" );
document.write( "Would one use the y=ab^x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498562 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FV = PV(1+(r/n))^nt    where FV is future value, pv is present value, r is<BR>\n" );
document.write( "annual interest rate, n is number of periods, t is years, we want to find FV <BR>\n" );
document.write( "note that PV is 500, r is 0.085, t is 3 and n is 2, then we have<BR>\n" );
document.write( "FV = 500(1 +(0.085/2))^(2*3)<BR>\n" );
document.write( "FV = 500(1.0425)^6<BR>\n" );
document.write( "FV = 500 * (1.2837)<BR>\n" );
document.write( "FV = 641.85<BR>\n" );
document.write( "Therefore the future value is $641.85\r<BR>\n" );
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document.write( " </SPAN>\n" );
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