document.write( "Question 69991: I NEED HELP ON ONE OF MY ALGEBRA QUESTION:\r
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document.write( "FIVE SISTERS' AGES ADD UP TP 211. THE OLDEST SISTER'S AGE WAS 3 TIMES THAT OF THE YOUNGEST. THE NEXT TO THE OLDEST WAS 2 YEARS YOUNGER THAN THE OLDEST AND THE MIDDLE SISTER WAS TWICE AS OLD AS TH YOUNGEST. THE REMAINING SISTER WAS 3 YEARS OLDER THAN THE YOUNGEST SISTER. WHAT IS THE AGE OF THE OLDEST SISTER? \n" );
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Algebra.Com's Answer #49852 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x= age of youngest \n" ); document.write( "Then 3x=age of oldest \n" ); document.write( "And 3x-2=age of next to oldest \n" ); document.write( "And 2x=age of middle sis \n" ); document.write( "And x+3=age of remaining sis\r \n" ); document.write( "\n" ); document.write( "And all this adds up to 211. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "x+3x+3x-2+2x+x+3=211 collect like terms\r \n" ); document.write( "\n" ); document.write( "10x+1=211 subtract 1 from both sides \n" ); document.write( "10x+1-1=211-1 \n" ); document.write( "10x=210 \n" ); document.write( "x=21 ---------------youngest \n" ); document.write( "3x=3*21=63-------------oldest \n" ); document.write( "3x-2=63-2=61------------------next oldest \n" ); document.write( "2x=2*21=42---------------------middle \n" ); document.write( "x+3=21+3=24--------------------remaining\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "21+63+61+42+24=211 \n" ); document.write( "211=211\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor \n" ); document.write( " \n" ); document.write( " |