document.write( "Question 827191: Solve for T
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Algebra.Com's Answer #498503 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Just rewrite it in exponential form. In general, \"log%28a%2C+%28p%29%29+=+n\" is equivalent to \"p+=+a%5En\". Using this pattern on your expression, and the fact that the base of \"ln\" is \"e\", we get:
\n" ); document.write( "\"T+=+e%5E5.47\"
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