document.write( "Question 827154: the sum of the digits of two digit number is 7. if the digits are interchanged, the resulting number is 27 more than the original number. find the original number.? \n" ); document.write( "
Algebra.Com's Answer #498475 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! all these are...are puzzles waiting to be solved \n" ); document.write( "Sum and more than=adding \n" ); document.write( "two digit number=## ex:(11, 35, 99, ...) \n" ); document.write( "adding the digits together looks like: 1+1=2 for 11, 3+5=8 for 35, 9+9=18 for 99 \n" ); document.write( "these can also be viewed as variables for example say xy=35 where x=3 and y=5 but if 3 where to be multiplied by 5 you don't get 35. so what this really looks like is 3*10+5=35 \n" ); document.write( "with this in mind lets start the problem \n" ); document.write( "we have numbers \n" ); document.write( "xy where \n" ); document.write( "yx where \n" ); document.write( "now you have 2 equations so I'll solve for x first and substitute it in 2nd equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "distribute the 10 \n" ); document.write( " \n" ); document.write( "add like terms \n" ); document.write( " \n" ); document.write( "add 9y to both sides and subtract 7 from both sides \n" ); document.write( " \n" ); document.write( "divide by 18 \n" ); document.write( " \n" ); document.write( "now simply solve for x by substituting in 5 for y \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "the original number should be \n" ); document.write( "Lets check \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "this is correct \n" ); document.write( " \n" ); document.write( " |