document.write( "Question 69986: I am having a difficult time with this problem. Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream. Someone please help? \n" ); document.write( "
Algebra.Com's Answer #49846 by ankor@dixie-net.com(22740)\"\" \"About 
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I am having a difficulty time with this problem. Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream.
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\n" ); document.write( "let x = speed of the stream:
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\n" ); document.write( "Speed upstream = (9-x)
\n" ); document.write( "Speed downstream = (9+x)
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\n" ); document.write( "Time = dist/speed
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\n" ); document.write( "Time upstream + time downstream = 3 hrs
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\n" ); document.write( "\"12%2F%28%289-x%29%29+%2B+12%2F%28%289%2Bx%29%29\" = 3
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\n" ); document.write( "Multiply equation by (9-x)(9+x), results
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\n" ); document.write( "12(9+x) + 12(9-x) = 3(9-x)(9+x)
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\n" ); document.write( "108 + 12x + 108 - 12x = 3(81 - x^2); difference of squares
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\n" ); document.write( "216 = 243 - 3x^2; 12x's eliminated
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\n" ); document.write( "0 = 243 - 216 - 3x^2
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\n" ); document.write( "+3x^2 = 243 - 216
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\n" ); document.write( "3x^2 = 27
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\n" ); document.write( "x^2 = 27/3
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\n" ); document.write( "x^2 = 9
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\n" ); document.write( "x = SqRt(9)
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\n" ); document.write( "x = 3 mph speed of the stream
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\n" ); document.write( "Check our solution: speed up is 6, speed down is 12
\n" ); document.write( "12/12 + 12/6 = 3 hrs
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\n" ); document.write( "Did this make sense to you?\r
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