document.write( "Question 827108: ms. russo is hiring an architect to create blue prints for a circular pool in her fenced in backyard. the rectangular fence neasures 50*4 square feet. the pool needs to be as big as possible within the given space. local building code states that pools have to be at least 3 feet from the fence.\r
\n" ); document.write( "\n" ); document.write( "a. sketch thefence and pool on the graph below
\n" ); document.write( "b. determine the diameter and circumference of the pool
\n" ); document.write( "c. if the bottom left of the fence is considered the origin on the Cartesian coordinate plane and the entire pool is in quadrant 1 then create the circle equation for the pool in circle radius form and in general form
\n" ); document.write( "I don't get how o find the center of the circle and the radius
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Algebra.Com's Answer #498441 by stanbon(75887)\"\" \"About 
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ms. russo is hiring an architect to create blue prints for a circular pool in her fenced in backyard. the rectangular fence neasures 50*4 sq ft = 200 sq ft.
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\n" ); document.write( "the pool needs to be as big as possible within the given space.
\n" ); document.write( "Let the rectangle be a square:
\n" ); document.write( "Each side is sqrt(200) = 10sqrt(2) ft.
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\n" ); document.write( "local building code states that pools have to be at least 3 feet from the fence.
\n" ); document.write( "radius of the pool is (5-3) = 2 ft
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\n" ); document.write( "a. sketch the fence and pool on the graph below
\n" ); document.write( "b. determine the diameter and circumference of the pool
\n" ); document.write( "Diameter = 4 ft; Circumference = 4pi ft
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\n" ); document.write( "c. if the bottom left of the fence is considered the origin on the Cartesian coordinate plane and the entire pool is in quadrant 1 then create the circle equation for the pool in circle radius form and in general form
\n" ); document.write( "Center at (2,2) because radius = 2.
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\n" ); document.write( "Equation: (x-2)^2 + (y-2)^2 = 4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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