document.write( "Question 826948: Shelly and Rachel both leave there house at the same time. They live 252 miles apart. Rachel is going 50 MPH. and Shelly is going 55 MPH. When will they meet?
\n" ); document.write( "a)2.4 hours
\n" ); document.write( "b)2.6 hours
\n" ); document.write( "c)4.6 hours
\n" ); document.write( "d)5 hours\r
\n" ); document.write( "\n" ); document.write( "I need help As soon as possible. Thank you for your help. I don't even know how to begin to solve the question.
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Algebra.Com's Answer #498384 by ankor@dixie-net.com(22740)\"\" \"About 
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Shelly and Rachel both leave there house at the same time.
\n" ); document.write( " They live 252 miles apart. Rachel is going 50 MPH. and Shelly is going 55 MPH.
\n" ); document.write( " When will they meet?
\n" ); document.write( ":
\n" ); document.write( "Let t = their travel time when they meet
\n" ); document.write( "When they meet, the sum of their travel distances will equal 252 mi
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "50t + 55t = 252
\n" ); document.write( "105t = 252
\n" ); document.write( "t = 252/105
\n" ); document.write( "t = 2.4 hrs
\n" ); document.write( ":
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\n" ); document.write( "Confirm this, find the actual distance each traveled
\n" ); document.write( "50*2.4 = 120 mi
\n" ); document.write( "55*2.4 = 132 mi
\n" ); document.write( "---------------
\n" ); document.write( "total d: 252 mi
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