document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826986>Question 826986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this question on my homework i dont get:\r<BR>\n" );
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document.write( "the sum of one number and thrice another is -15.the difference of the fisrt number and the second number is 10. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498363 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of one number and thrice another is -15.the difference of the fisrt number and the second number is 10. find the numbers<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 3y = -15<BR>\n" );
document.write( "x - y = 10<BR>\n" );
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document.write( "Subtract and solve for \"y\":<BR>\n" );
document.write( "4y = -25<BR>\n" );
document.write( "y = 6 1/4<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x - 6 1/4 = 10<BR>\n" );
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document.write( "x = 3 3/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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