document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826919>Question 826919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 4 times cosine of theta plus 1 = 2 times cosine of theta for theta greater than or equal to 0 but less than 2 pi..  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498322 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 4 times cosine of theta plus 1 = 2 times cosine of theta for theta greater than or equal to 0 but less than 2 pi.. <BR>\n" );
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document.write( "4cos(t)+1 = 2cos(t) for 0<= t <2pi<BR>\n" );
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document.write( "2cos(t) = -1<BR>\n" );
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document.write( "cos(t) = -1/2<BR>\n" );
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document.write( "t = 180-60 or 180+60<BR>\n" );
document.write( "t = 120 degrees or 240 degrees<BR>\n" );
document.write( "t = (2/3)pi or (4/3)pi radians<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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