document.write( "Question 826742: solve for y the equation 3(y2+3)=28y. \n" ); document.write( "
Algebra.Com's Answer #498313 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
First of all, please use the \"^\" character (shift 6) to indicate exponents. Your equation should read:
\n" ); document.write( "3(y^2+3)=28y

\n" ); document.write( "\"3%28y%5E2%2B3%29=28y\"
\n" ); document.write( "To solve this we need it in standard form: \"ay%5E2%2Bby%2Bc+=+0\". So we start by transforming the equation. First, simplify:
\n" ); document.write( "\"3y%5E2%2B9=28y\"
\n" ); document.write( "Subtract 28y:
\n" ); document.write( "\"3y%5E2-28y%2B9=0\"
\n" ); document.write( "Next, factor (or use the Quadratic Formula):
\n" ); document.write( "\"%283x-1%29%28x-9%29+=+0\"
\n" ); document.write( "From the Zero Product Property:
\n" ); document.write( "3x-1 = 0 or x-9 = 0
\n" ); document.write( "Solving these we get:
\n" ); document.write( "\"x+=+1%2F3\" or \"x+=+9\"
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