document.write( "Question 826871: We are having a hard time understanding why the Arcsin (-1) is -90 degrees. We know that the reference triangle is a 45,45,90 degree triangle. Sin is opp/adj so this makes no sense to me. Please explain this for me.
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\n" ); document.write( " Caleb \n" ); document.write( "

Algebra.Com's Answer #498301 by rothauserc(4718) $\"\"$ $\"About$

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The graph of the sine function depicts a periodic function which is not 1-1 unless we restrict the domain where the function is 1-1, the restriction is on the interval [-pi/2, pi/2] where pi is 180 degrees. Note that the x-axis is in radians (i.e. there are 2pi radians in a circle, 90 degrees is pi/2 radians)\r
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\n" ); document.write( "\n" ); document.write( "We see that the graph of y = arcsin x is 1-1 over [-1, 1], y axis is in radians\r
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