document.write( "Question 826685: How can I algebraically find all zeros of y= (x)= 3sin(2x) + cos(x) over the interval -(pi)less than or equal to x which is less than or equal to (pi)? \n" ); document.write( "
Algebra.Com's Answer #498287 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! Finding the zeros of \n" ); document.write( "y = 3sin(2x) + cos(x) \n" ); document.write( "means finding the solutions to: \n" ); document.write( "0 = 3sin(2x) + cos(x) \n" ); document.write( "Solving Trig equations like this usually starts with using algebra and/or Trig properties to transform the equation into one or more equations of the general form: \n" ); document.write( "TrigFunction(expression) = number \n" ); document.write( "To solve this equation we will start by using the sin(2x) = 2sin(x)cos(x) identity. Substituting for sin(2x) we get: \n" ); document.write( "0 = 3(2sin(x)cos(x)) + cos(x) \n" ); document.write( "which simplifies to: \n" ); document.write( "0 = 6sin(x)cos(x) + cos(x) \n" ); document.write( "Now we can factor out cos(x): \n" ); document.write( "0 = cos(x)(6sin(x)+1) \n" ); document.write( "From the Zero Product Property: \n" ); document.write( "cos(x) = 0 or 6sin(x)+1 = 0 \n" ); document.write( "(Note how we now have two equations. This is one way to get more than one equation from a single equation.) Solving these we get: \n" ); document.write( "cos(x) = 0 or sin(x) = -1/6 \n" ); document.write( "We now have the equations in the desired form. \n" ); document.write( "Next we find the general solution. \n" ); document.write( "For cos(x) = 0 we should recognize that 0 is a special angle value for cos. We should know that cos is 0 at \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For sin(x) = -1/6 we should recognize that 1/6 is not a special angle value for sin. So we will need our calculators. We will use \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Together, the general solution equations for 0 = 3sin(2x) + cos(x) are: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The general solution equations express the infinite set of solutions to the equation. Many problems, like this one, ask for solutions which are in a given interval. This time the interval is \n" ); document.write( "From \n" ); document.write( "If n = 0 then \n" ); document.write( "If n = 1 (or greater) then x is too large for the interval. \n" ); document.write( "If n = -1 (or smaller) then x is too small for the interval. \n" ); document.write( "From \n" ); document.write( "If n = 0 (or larger) then x is too large for the interval. \n" ); document.write( "If n = -1 then \n" ); document.write( "If n = -2 or smaller then x is too small for the interval. \n" ); document.write( "From \n" ); document.write( "If n = 0 (or larger) then x is too large for the interval. \n" ); document.write( "If n = -1 then \n" ); document.write( "If n = -2 or smaller then x is too small for the interval. \n" ); document.write( "From \n" ); document.write( "If n = 0 then \n" ); document.write( "If n = 1 (or greater) then x is too large for the interval. \n" ); document.write( "If n = -1 (or smaller) then x is too small for the interval. \n" ); document.write( "Altogether, the solutions to 0 = 3sin(2x) + cos(x) (and therefore the zeros of f(x) = 3sin(2x) + cos(x)) within the specified interval are: \n" ); document.write( " \n" ); document.write( "P.S. Feel free to replace the |