document.write( "Question 826721: Three girls were stringing beads. There were a total of 195 beads in all and they were shared in a ratio of 1/2:1/3:1/4. How many beads did each of the girls receive?
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Algebra.Com's Answer #498252 by KMST(5328)\"\" \"About 
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ONE WAY TO LOOK AT IT:
\n" ); document.write( "Multiplying the proportions 1/2:1/3:1/4 times 12 we get
\n" ); document.write( "12/2:12/3:12/4 or 6:4:3 .
\n" ); document.write( "That means that for every 6 + 4 + 3 = 13 beads, they got 6, 4, and 3 beads respectively.
\n" ); document.write( "195/13 = 15 , so we can distribute 13 beads 15 times
\n" ); document.write( "with one girl receiving 15*6 = 90 beads,
\n" ); document.write( "the other one getting 15*4 = 60 beads,
\n" ); document.write( "and the third one getting 15*3 = 45 beads.
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\n" ); document.write( "ANOTHER WAY:
\n" ); document.write( "They got (1/2)x, (1/3)x, and (1/4)x respectively for some number x, and
\n" ); document.write( "(1/2)x + (1/3)x + (1/4)x = 195
\n" ); document.write( "(1/2+1/3+1/4)x = 195
\n" ); document.write( "(6/12+4/12+3/12)x = 195
\n" ); document.write( "(13/12)x = 195
\n" ); document.write( "x = 195(12/13)
\n" ); document.write( "x = 195*12/13
\n" ); document.write( "x = 180
\n" ); document.write( "So they got
\n" ); document.write( "(1/2)180 = 90,
\n" ); document.write( "(1/3)180 = 60, and
\n" ); document.write( "(1/4)180 = 45 respectively.
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