document.write( "Question 826767: The difference between two numbers is 28. he larger number is 8 less than twice the smaller number. Find both numbers \n" ); document.write( "
Algebra.Com's Answer #498242 by MathLover1(20850)\"\" \"About 
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let numbers be \"x\" (larger) and \"y\" (smaller)\r
\n" ); document.write( "\n" ); document.write( "if the difference between two numbers is \"28\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x-y=28\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "if the larger number is \"8\" less than twice the smaller number, we have\r
\n" ); document.write( "\n" ); document.write( "\"x=2y-8\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "now solve this system:\r
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\n" ); document.write( "\n" ); document.write( "\"x-y=28\"....eq.1
\n" ); document.write( "\"x=2y-8\"....eq.2
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\n" ); document.write( "\n" ); document.write( "\"x-y=28\"....eq.1...substitute \"x\" from eq.2\r
\n" ); document.write( "\n" ); document.write( "\"2y-8-y=28\"....solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"2y-y=28%2B8\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=36%29\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.2 and find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2y-8\"....eq.2..............plug in \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2A36-8\"\r
\n" ); document.write( "\n" ); document.write( "\"x=72-8\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=64%29\"\r
\n" ); document.write( "\n" ); document.write( "so, your numbers are \"64\" and \"36\"\r
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