document.write( "Question 826760: how do i do this problem by using substitution
\n" ); document.write( "4x+4y=24
\n" ); document.write( "y=6x+20
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Algebra.Com's Answer #498235 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " $\"4x%2B4y=24+\"$ ....eq.1
\n" ); document.write( " $\"y=6x%2B20\"$ ....eq.2
\n" ); document.write( "______________________\r
\n" ); document.write( "\n" ); document.write( " $\"4x%2B4y=24+\"$ ....eq.1.............substitute $\"y\"$ from eq.2\r
\n" ); document.write( "\n" ); document.write( " $\"4x%2B4%286x%2B20%29=24+\"$ ..........solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4x%2B24x%2B80=24+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"28x=24-80+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"28x=-56+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=-56%2F28+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28x=-2%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "now, go back to eq.2 and find $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=6x%2B20\"$ ....eq.2.........plug in value of $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=6%28-2%29%2B20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=-12%2B20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28y=8%29\"$ \r
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