document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826707>Question 826707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the standard form of the equation of the line that passes through the point (6,4) and has a slope of 8/5. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498218 by </B><A HREF=/tutors/aboutme.mpl?userid=yourstruly><B>yourstruly(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=yourstruly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you should remember the formula: y-y1= m(x-x1)<BR>\n" );
document.write( "m= gradient/slope<BR>\n" );
document.write( "x1,y1= coordinates of the point that the line passes through \r<BR>\n" );
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document.write( "In this question our slope is 5/8 and our x and y coordinates are 6 and 4 respectively. <BR>\n" );
document.write( "When we plug this into the formula above we get:\r<BR>\n" );
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document.write( "y-4= 5/8(x-6)<BR>\n" );
document.write( "y-4= 5/8x-15/4<BR>\n" );
document.write( "y=5/8x+1/4\r<BR>\n" );
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document.write( "Now, we have to put this equation into standard form which is <BR>\n" );
document.write( "ax+by+c=0<BR>\n" );
document.write( "8y=5x+2<BR>\n" );
document.write( "5x+2-8y=0----- this is the answer  </SPAN>\n" );
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