document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69951>Question 69951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation that satisfies the given conditions.\r<BR>\n" );
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document.write( "perpendicular to y=2x+7, through (0,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49819 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE SLOPE OF THIS LINE (Y=2X+7) IS 2. THUS THE LINE PERPENDICULAR HAS A SLOPE OF -1/2<BR>\n" );
document.write( "WITH A SLOPE OF -1/2 THROUGH (0,0) WE HAVE THE EQUATION <BR>\n" );
document.write( "Y=-X/2 </SPAN>\n" );
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