document.write( "Question 69944: Two investments are made totaling $16,000. For a certain year, these investments yield $970 in simple interest. Part of the $16,000 is invested at 5% and the rest at 7%. How much is invested at 7%? \n" ); document.write( "
Algebra.Com's Answer #49816 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
.07x+.05(16000-x)=970
\n" ); document.write( ".07x+800-.05x=970
\n" ); document.write( ".02x=970-800
\n" ); document.write( ".02x=170
\n" ); document.write( "x=170/.02
\n" ); document.write( "x=8500 invested @ 7%
\n" ); document.write( "16000-8500=7500 invested @ 5%
\n" ); document.write( "proof
\n" ); document.write( ".07*8500+.05*7500=970
\n" ); document.write( "595+375=970
\n" ); document.write( "970=970
\n" ); document.write( "
\n" );