document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826570>Question 826570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hight of an object moving vertically is given by s= -16t^2+60t+112 where s is measured in feet and t is measured in seconds. \r<BR>\n" );
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document.write( "Find the objects velocity when t=0 <BR>\n" );
document.write( "find its maximum hight and when it occurs<BR>\n" );
document.write( "Find the velocity when s=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #498155 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=498155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The height of an object moving vertically is given by <BR>\n" );
document.write( "s(t) = -16t^2+60t+112 where s is measured in feet and t is measured in seconds. <BR>\n" );
document.write( "Find the objects velocity when t=0 <BR>\n" );
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document.write( "Velocity at time = t is the derivative of \"s\":<BR>\n" );
document.write( "s'(t) = -32t+60<BR>\n" );
document.write( "s'(0) = 60 ft/sec<BR>\n" );
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document.write( "find its maximum hight and when it occurs<BR>\n" );
document.write( "Max height occurs when t = -b/(2a) = -60/(-32) = 1.875 sec<BR>\n" );
document.write( "s(1.875) = 168.25 ft.<BR>\n" );
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document.write( "Find the velocity when s=0<BR>\n" );
document.write( "When s = 0 the object will be on the groud.<BR>\n" );
document.write( "Its velocity will be zero.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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