document.write( "Question 826275: Joe ken and mike are three bicycle riders starting together and traveling around a track that is 1/3 of a mile. One travels 4mph, one 6mph, and one 8mph. In how many minutes will they next be together at the starting point for the first time. \n" ); document.write( "
Algebra.Com's Answer #498073 by ankor@dixie-net.com(22740)\"\" \"About 
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Joe ken and mike are three bicycle riders starting together and traveling around a track that is 1/3 of a mile.
\n" ); document.write( " One travels 4mph, one 6mph, and one 8mph.
\n" ); document.write( " In how many minutes will they next be together at the starting point for the first time.:
\n" ); document.write( "Find the time for JOe to circle the track at 4 mph in minutes. time = dist/speed
\n" ); document.write( "\"%281%2F3%29%2F4\" * 60 =
\n" ); document.write( "which is
\n" ); document.write( "\"1%2F3\"*\"1%2F4\"*60 = 5 min
\n" ); document.write( ":
\n" ); document.write( "Find the time for Ken at 6 mph
\n" ); document.write( "\"1%2F3\"*\"1%2F6\"*60 = 3\"1%2F3\" min:
\n" ); document.write( ":
\n" ); document.write( "Mike is twice as fast as Joe, therefore
\n" ); document.write( "\"5%2F2\" = 2\"1%2F2\" min for Mike
\n" ); document.write( ":
\n" ); document.write( "Try 30 min for them all to be at the starting point
\n" ); document.write( ":
\n" ); document.write( "30/5 = 6 times around the track by Joe
\n" ); document.write( "30/3.3333 = 9 times by Ken
\n" ); document.write( "30/2.5 = 12 times by Mike\r
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