document.write( "Question 826437: A rectangle is 5cm longer than its wide. If the length and breadth are increased by 2cm each, the area increases by 50cm2. FInd the dimensions of the original rectangle \n" ); document.write( "
Algebra.Com's Answer #498064 by josgarithmetic(39617)\"\" \"About 
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x length
\n" ); document.write( "w wide\r
\n" ); document.write( "\n" ); document.write( "\"w=x%2B5\";
\n" ); document.write( "If x+2 and w+2, then area is increased, +50 cm*cm.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"xw=A\", A for area.
\n" ); document.write( "\"%28x%2B2%29%28w%2B2%29=A%2B50\";
\n" ); document.write( "\"w=x%2B5\".
\n" ); document.write( "'
\n" ); document.write( "Let us substitute for w into the two area equations.
\n" ); document.write( "\"x%28x%2B5%29=A\",
\n" ); document.write( "\"highlight_green%28x%5E2%2B5x=A%29\".----Original area
\n" ); document.write( "'
\n" ); document.write( "\"%28x%2B2%29%28%28x%2B5%29%2B2%29=A%2B50\"-----for Increased dimensions area
\n" ); document.write( "\"%28x%2B2%29%28x%2B7%29=A%2B50\"
\n" ); document.write( "\"x%5E2%2B9x%2B14=A%2B50\", and remember we can also substitute for A;
\n" ); document.write( "\"x%5E2%2B9x%2B14=%28x%5E2%2B5x%29%2B50\"
\n" ); document.write( "\"x%5E2%2B9x%2B0=x%5E2%2B5x%2B36\"
\n" ); document.write( "\"9x=5x%2B36\"
\n" ); document.write( "\"4x=36\"
\n" ); document.write( "\"highlight%28x=9%29\"
\n" ); document.write( "-
\n" ); document.write( "Now to find value of w:
\n" ); document.write( "\"w=x%2B5\"
\n" ); document.write( "\"w=9%2B5\"
\n" ); document.write( "\"highlight%28w=14%29\"
\n" ); document.write( "
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