document.write( "Question 69885: Is the following trinomial a perfect square:
\n" ); document.write( "x^2 - 6x + 9\r
\n" ); document.write( "\n" ); document.write( "I do not understand what method I am to use to figure this out, can anyone help me out please? Thank you
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Algebra.Com's Answer #49805 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+-+6x+%2B+9=0\" Set equation equal to zero
\n" ); document.write( "\"x%5E2+-+6x+=+-9\" Get similar factors to one side, ie all x's to one side
\n" ); document.write( "\"x%5E2+-+6x+%2B+9+=+-9%2B9\" Take half of the 2nd coefficient (6) and square it, then add it to both sides (note: when you take half of the 2nd coefficient, it will be part of the perfect square)
\n" ); document.write( "\"x%5E2+-+6x+%2B+9+=+0\" You'll be left with this after simplification
\n" ); document.write( "\"%28x-3%29%5E2+=+0\"Factor the polynomial (note if FOILed, (x-3)^2 becomes x^2-6x+9)
\n" ); document.write( "Since the answer is in the form (x-b)^2=0 and there is no extra numbers left over, the original polynomial is a perfect square.
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