document.write( "Question 69899: the rectangle has a premiter of 64cm.
\n" ); document.write( "the length needs 4cm. to be twice the size as the width
\n" ); document.write( "please slove and explain
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Algebra.Com's Answer #49798 by ptaylor(2198)\"\" \"About 
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Perimeter of rectangle=2*length+2*width=2L+2W=64 cm\r
\n" ); document.write( "\n" ); document.write( "Let x=width
\n" ); document.write( "Then 2x-4=length
\n" ); document.write( " 2L+2W=2x+2(2x-4)=64cm\r
\n" ); document.write( "\n" ); document.write( "2x+2(2x-4)=64 cm get rid of parens\r
\n" ); document.write( "\n" ); document.write( "2x+4x-8=64 cm add 8 to both sides\r
\n" ); document.write( "\n" ); document.write( "2x+4x-8+8=64+8 collect like terms
\n" ); document.write( "6x=72 divide both sides by 6
\n" ); document.write( "x=12 cm---------------width
\n" ); document.write( "2x-4=2*12-4=20 cm-------------length\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "2L+2W=40+24=64cm \r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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