document.write( "Question 69899: the rectangle has a premiter of 64cm.
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document.write( "the length needs 4cm. to be twice the size as the width
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document.write( "please slove and explain \n" );
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Algebra.Com's Answer #49798 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Perimeter of rectangle=2*length+2*width=2L+2W=64 cm\r \n" ); document.write( "\n" ); document.write( "Let x=width \n" ); document.write( "Then 2x-4=length \n" ); document.write( " 2L+2W=2x+2(2x-4)=64cm\r \n" ); document.write( "\n" ); document.write( "2x+2(2x-4)=64 cm get rid of parens\r \n" ); document.write( "\n" ); document.write( "2x+4x-8=64 cm add 8 to both sides\r \n" ); document.write( "\n" ); document.write( "2x+4x-8+8=64+8 collect like terms \n" ); document.write( "6x=72 divide both sides by 6 \n" ); document.write( "x=12 cm---------------width \n" ); document.write( "2x-4=2*12-4=20 cm-------------length\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "2L+2W=40+24=64cm \r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |