document.write( "Question 69888: Lawanda and Betty both drive the same distance to the shore. By driving 15 miles per hour faster than Betty, Lawanda can get there in 3 hours while Betty takes 4 hours. How fast does each drive? \n" ); document.write( "

Algebra.Com's Answer #49797 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let x= Betty's speed
\n" ); document.write( "Then x+15=Lawanda's speed\r
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\n" ); document.write( "\n" ); document.write( "Distance(d)=rate(r) times time(t) or d=rt \r
\n" ); document.write( "\n" ); document.write( "Distance Betty drives=4x
\n" ); document.write( "Distance Lawanda drives=3(x+15)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that they both drive the same distance. So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "4x=3(x+15) get rid of parens
\n" ); document.write( "4x=3x+45 subtract 3x from both sides
\n" ); document.write( "4x-3x=3x-3x+45 collect like terms
\n" ); document.write( "x=45 mph--------------------------------------Betty's speed\r
\n" ); document.write( "\n" ); document.write( "x+15=45+15=60 mph ------------------------Lawanda's speed\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "3*60=4*45
\n" ); document.write( "180=180
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