document.write( "Question 826194: find three consecutive even integer such that three times the first equals the sum of the other two. \n" ); document.write( "
Algebra.Com's Answer #497934 by Seutip(231)![]() ![]() You can put this solution on YOUR website! Let x - be the first integer \n" ); document.write( " x+2 - be the second integer \n" ); document.write( " x+4 - be the third integer\r \n" ); document.write( "\n" ); document.write( "since they are consecutive even we add 2, each. :)\r \n" ); document.write( "\n" ); document.write( "3(x) = x+2 + x+4 (This is how you translate it to mathematical equation. \n" ); document.write( "3x = 2x+6 \n" ); document.write( "x=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 6 \n" ); document.write( "x+2 = 6+2 = 8 \n" ); document.write( "x+4 = 6+4 = 10 \n" ); document.write( "So the three consecutive integers are \n" ); document.write( "6, 8 and 10 :) \n" ); document.write( " |