document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826187>Question 826187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of four consecutive even integers is 2 more than five times the first integer.Find the smallest integer.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497927 by </B><A HREF=/tutors/aboutme.mpl?userid=Seutip><B>Seutip(231)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Seutip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Seutip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497927\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It's easy:\r<BR>\n" );
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document.write( "Let x - be the first integer, since it is consecutive even we must add 2<BR>\n" );
document.write( "    x+2 - be the second integer<BR>\n" );
document.write( "    x+4 - be the third integer (x+2+2)<BR>\n" );
document.write( "    x+6 - be the fourth integer (x+2+2+2)\r<BR>\n" );
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document.write( "x+x+2+x+4+x+6 = 5(x)+2 This is how you interpret it.\r<BR>\n" );
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document.write( "Simplify then find x :)\r<BR>\n" );
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document.write( "4x+12=5x+2<BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "So the first integer is 10, next is 12, then 14, and 16.\r<BR>\n" );
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document.write( "The smallest integer is 10. :) \r<BR>\n" );
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document.write( "HOPE THAT HELPS!\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "x+x+2+x+4+x+6 = 5(x)+2<BR>\n" );
document.write( "10+10+2+10+4+10+6 = 5(10) +2<BR>\n" );
document.write( "52=52 </SPAN>\n" );
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