document.write( "Question 826098: determine the equation of the hyperbola whose vertices are the foci of the ellipse 11x^2 + 7y^2 + 14y - 70 = 0 and its foci are the vertices of the given ellipse.\r
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Algebra.Com's Answer #497920 by lwsshak3(11628)\"\" \"About 
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determine the equation of the hyperbola whose vertices are the foci of the ellipse 11x^2 + 7y^2 + 14y - 70 = 0 and its foci are the vertices of the given ellipse.
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\n" ); document.write( "11x^2 + 7y^2 + 14y - 70 = 0
\n" ); document.write( "complete the square:
\n" ); document.write( "11x^2+7(y^2+2y+1)=70+7=77
\n" ); document.write( "\"x%5E2%2F7%2B%28y%2B1%29%5E2%2F11=1\"
\n" ); document.write( "This is an equation of an ellipse with vertical major axis.
\n" ); document.write( "Its standard form: \"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\", a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given equation of th ellipse:
\n" ); document.write( "center:(0,-1)
\n" ); document.write( "a^2=11
\n" ); document.write( "a=√11≈3.32
\n" ); document.write( "vertices: (0,-1±a)=(0,-1±√11)=(0,-1±3.32)=(0,-4.32)and(=(0,+2.32)
\n" ); document.write( "b^2=7
\n" ); document.write( "b=√7
\n" ); document.write( "c^2=a^2-b^2=11-7=4
\n" ); document.write( "c=±2
\n" ); document.write( "foci:(0,-1±c)=(0,-1±2)=(0,-3)and(=(0,+1)
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\n" ); document.write( "For given hyperbola:
\n" ); document.write( "assume same center as given ellipse: (0,-1)
\n" ); document.write( "Hyperbola has a vertical transverse axis:
\n" ); document.write( "Its standard form of equation: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "a=2(foci of ellipse)
\n" ); document.write( "a^2=4
\n" ); document.write( "c^2=11(vertex of ellipse)
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "b^2=c^2-a^2=11-4=7
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( "\"%28y%2B1%29%5E2%2F4-x%5E2%2F7=1\"\r
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