document.write( "Question 826170: A man buys milk at 60 P per liter, adds 1/3rd of water to it and sells the mixture at 72 P per liter. The profit percentage is.......? \n" ); document.write( "
Algebra.Com's Answer #497918 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! He bought some B liters of milk at 60 P money units, and added \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "His revenue upon selling all of his mixture is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summarize: \n" ); document.write( "Cost = \n" ); document.write( "Revenue = \n" ); document.write( "Profit = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Profit percentage based on revenue woould be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you meant, based on cost, then divide profit by cost, and then multiply by 100. \n" ); document.write( " |