document.write( "Question 826170: A man buys milk at 60 P per liter, adds 1/3rd of water to it and sells the mixture at 72 P per liter. The profit percentage is.......? \n" ); document.write( "
Algebra.Com's Answer #497918 by josgarithmetic(39617)\"\" \"About 
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He bought some B liters of milk at 60 P money units, and added \"1%2F3%29B\" liters of water. The mixture is \"B%2B%281%2F3%29B\" liters containing the B liters of milk.\r
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\n" ); document.write( "\n" ); document.write( "His revenue upon selling all of his mixture is \"B%281%2B1%2F3%29%2A72\" P money units.\r
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\n" ); document.write( "\n" ); document.write( "Summarize:
\n" ); document.write( "Cost = \"B%2A60\" P units
\n" ); document.write( "Revenue = \"B%281%2B1%2F3%29%2A72\" P units
\n" ); document.write( "Profit = \"Revenue+-+Cost+=+B%284%2F3%29%2A72-B%2A60+=+B%28%284%2F3%2972-60%29\" of P money units\r
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\n" ); document.write( "\n" ); document.write( "Profit percentage based on revenue woould be \"100%2A%28B%28%284%2F3%2972-60%29%29%2F%28B%281%2B1%2F3%29%2A72%29\", if that was what you meant; which you can simplify and compute.\r
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\n" ); document.write( "\n" ); document.write( "If you meant, based on cost, then divide profit by cost, and then multiply by 100.
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