document.write( "Question 825948: A sum of money invested at 6% interest and a second sum at 5% yield a total annual income of $500. the first sum exceeds the 2nd by $100. Find each investment.
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Algebra.Com's Answer #497790 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
let the second sum be x and the first sum is x+100, therefore
\n" ); document.write( "(x+100)*(0.06) + x*(0.05) = 500
\n" ); document.write( "0.06x + 6 +0.05x = 500
\n" ); document.write( "0.11x = 494
\n" ); document.write( "second sum is $4490.90
\n" ); document.write( "first sum is $4590.90
\n" ); document.write( "check our answers
\n" ); document.write( "4590.90 * 0.06 + 4490.90 * 0.05 = 500
\n" ); document.write( "275.45 + 224.55 = 500
\n" ); document.write( "500 = 500
\n" ); document.write( "answer checks :-)\r
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