document.write( "Question 825948: A sum of money invested at 6% interest and a second sum at 5% yield a total annual income of $500. the first sum exceeds the 2nd by $100. Find each investment.
\n" );
document.write( "I need the solution. Thank you. :* \n" );
document.write( "
Algebra.Com's Answer #497790 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let the second sum be x and the first sum is x+100, therefore \n" ); document.write( "(x+100)*(0.06) + x*(0.05) = 500 \n" ); document.write( "0.06x + 6 +0.05x = 500 \n" ); document.write( "0.11x = 494 \n" ); document.write( "second sum is $4490.90 \n" ); document.write( "first sum is $4590.90 \n" ); document.write( "check our answers \n" ); document.write( "4590.90 * 0.06 + 4490.90 * 0.05 = 500 \n" ); document.write( "275.45 + 224.55 = 500 \n" ); document.write( "500 = 500 \n" ); document.write( "answer checks :-)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |