document.write( "Question 826008: Ship A was sailing due to South at the rate of 6 miles per hour and another ship B was sailing due to East at the rate of 8 miles per hour. At 4 PM ship B crossed the position where hip A was 2 hours before.
\n" ); document.write( "1) At what rate were they approaching or separating at 3 PM ?
\n" ); document.write( "2) At what rate were they changing the distance between them at 5 PM ?
\n" ); document.write( "3) When was the distance between them not changing ?
\n" ); document.write( "

Algebra.Com's Answer #497784 by Alan3354(69443)\"\" \"About 
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Ship A was sailing due to South at the rate of 6 miles per hour and another ship B was sailing due to East at the rate of 8 miles per hour. At 4 PM ship B crossed the position where hip A was 2 hours before.
\n" ); document.write( "Use 2 PM as the starting point.
\n" ); document.write( "Ship A is 12 miles North of it, and ship B is at the point.
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\n" ); document.write( "Find the distance between the ships as a function of time (in hours).
\n" ); document.write( "t = 0 at the starting point.
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\n" ); document.write( "Ship A's distance from the SP is 12 - 6t miles
\n" ); document.write( "Ship B's distance from the SP is 8t miles
\n" ); document.write( "The distance between them is the hypotenuse of a right triangle.
\n" ); document.write( "\"s%5E2+=+%2812-6t%29%5E2+%2B+%288t%29%5E2+=+100t%5E2+-+144t+%2B+144\"
\n" ); document.write( "\"s+=+sqrt%28100t%5E2+-+144t+%2B+144%29\"
\n" ); document.write( "Find the relative speed, ds/dt
\n" ); document.write( "ds/dt = \"%281%2F2%29%2Fsqrt%28100t%5E2+-+144t+%2B+144%29%2A%28200t+-+144%29\"
\n" ); document.write( "s'(t) = \"%28100t-72%29%2Fsqrt%28100t%5E2+-+144t+%2B+144%29\"
\n" ); document.write( "s'(t) = \"%2850t-36%29%2Fsqrt%2825t%5E2+-+36t+%2B+36%29\"
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\n" ); document.write( "1) At what rate were they approaching or separating at 3 PM ?
\n" ); document.write( "3 PM is t = 1
\n" ); document.write( "s'(1) = \"%2850-36%29%2Fsqrt%2825+-+36+%2B+36%29\"
\n" ); document.write( "= 14/5 = 2.8 mi/hr
\n" ); document.write( "----------------------------------------------
\n" ); document.write( "2) At what rate were they changing the distance between them at 5 PM ?
\n" ); document.write( "5 PM --> t = 3
\n" ); document.write( "s'(3) = \"%2850%2A3-36%29%2Fsqrt%2825%2A9+-+36%2A3+%2B+36%29\"
\n" ); document.write( "= \"114%2Fsqrt%28153%29\"
\n" ); document.write( "= \"38%2Fsqrt%2817%29\"
\n" ); document.write( "=~ 9.216 mi/hr
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\n" ); document.write( "3) When was the distance between them not changing ?
\n" ); document.write( "s'(t) = \"%2850t-36%29%2Fsqrt%2825t%5E2+-+36t+%2B+36%29\" = 0
\n" ); document.write( "50t-36 = 0
\n" ); document.write( "t = 0.72 hrs past 2 PM
\n" ); document.write( "t = 2:43:12 PM
\n" ); document.write( "-------------------------
\n" ); document.write( "The speeds in parts 1 & 2 are both separating, since they're past the time in part 3.
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\n" ); document.write( "It appears to be a simple problem, but is complex. At least it's a right triangle.
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