document.write( "Question 826008: Ship A was sailing due to South at the rate of 6 miles per hour and another ship B was sailing due to East at the rate of 8 miles per hour. At 4 PM ship B crossed the position where hip A was 2 hours before.
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document.write( "1) At what rate were they approaching or separating at 3 PM ?
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document.write( "2) At what rate were they changing the distance between them at 5 PM ?
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document.write( "3) When was the distance between them not changing ? \n" );
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Algebra.Com's Answer #497784 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Ship A was sailing due to South at the rate of 6 miles per hour and another ship B was sailing due to East at the rate of 8 miles per hour. At 4 PM ship B crossed the position where hip A was 2 hours before. \n" ); document.write( "Use 2 PM as the starting point. \n" ); document.write( "Ship A is 12 miles North of it, and ship B is at the point. \n" ); document.write( "------ \n" ); document.write( "Find the distance between the ships as a function of time (in hours). \n" ); document.write( "t = 0 at the starting point. \n" ); document.write( "--- \n" ); document.write( "Ship A's distance from the SP is 12 - 6t miles \n" ); document.write( "Ship B's distance from the SP is 8t miles \n" ); document.write( "The distance between them is the hypotenuse of a right triangle. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Find the relative speed, ds/dt \n" ); document.write( "ds/dt = \n" ); document.write( "s'(t) = \n" ); document.write( "s'(t) = \n" ); document.write( "============================================ \n" ); document.write( "1) At what rate were they approaching or separating at 3 PM ? \n" ); document.write( "3 PM is t = 1 \n" ); document.write( "s'(1) = \n" ); document.write( "= 14/5 = 2.8 mi/hr \n" ); document.write( "---------------------------------------------- \n" ); document.write( "2) At what rate were they changing the distance between them at 5 PM ? \n" ); document.write( "5 PM --> t = 3 \n" ); document.write( "s'(3) = \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "=~ 9.216 mi/hr \n" ); document.write( "------------------------------------------ \n" ); document.write( "3) When was the distance between them not changing ? \n" ); document.write( "s'(t) = \n" ); document.write( "50t-36 = 0 \n" ); document.write( "t = 0.72 hrs past 2 PM \n" ); document.write( "t = 2:43:12 PM \n" ); document.write( "------------------------- \n" ); document.write( "The speeds in parts 1 & 2 are both separating, since they're past the time in part 3. \n" ); document.write( "=========================================== \n" ); document.write( "It appears to be a simple problem, but is complex. At least it's a right triangle. \n" ); document.write( " |