document.write( "Question 826013: divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16 kindly help me to solve it with required steps/details. \n" ); document.write( "
Algebra.Com's Answer #497772 by stanbon(75887)\"\" \"About 
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divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16
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\n" ); document.write( "Using 2 variables::
\n" ); document.write( "Equations:
\n" ); document.write( "x + y = 95
\n" ); document.write( "(1/2)x - (1/5)y = 16\r
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\n" ); document.write( "Modify:
\n" ); document.write( "x + y = 95
\n" ); document.write( "5x - 2y = 160
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\n" ); document.write( "Modify:
\n" ); document.write( "5x + 5y = 475
\n" ); document.write( "5x - 2y = 160
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\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "7y = 315
\n" ); document.write( "y = 45
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\n" ); document.write( "The x = 95-45 = 50
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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