document.write( "Question 826000: Hello. I'm hoping someone would answer this. I needed it as in ASAP. Thank you. \r
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\n" ); document.write( "\n" ); document.write( " A sum of money invested at 6% interest and a second sum at 5% yield a total annual income of $500. the first sum exceeds the 2nd by $100. Find each investment.
\n" ); document.write( "I need the solution. Thank you. :*
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Algebra.Com's Answer #497763 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"x\"= amount, in $, invested at 5%
\n" ); document.write( "\"x%2B100\"= amount, in $, invested at 6%
\n" ); document.write( "$\"0.05x\"= 5% annual interest on $\"x\"
\n" ); document.write( "$\"0.06%28x%2B100%29\"= $\"0.06x%2B6\"= 6% annual interest on $\"x%2B100\"
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\n" ); document.write( "The equation is \"0.06x%2B6=500\"
\n" ); document.write( "Solving:
\n" ); document.write( "\"0.06x%2B6=500\"
\n" ); document.write( "\"0.06x=500-6\"
\n" ); document.write( "\"0.06x=494\"
\n" ); document.write( "\"x=494%2F0.06\"
\n" ); document.write( "\"highlight%28x=8233.33%29\"
\n" ); document.write( "\"x%2B100=8233.33%2B100\"
\n" ); document.write( "\"highlight%28x%2B100=8333.33%29\"
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