document.write( "Question 825980: a father is three times as old as his son .5years ago fathers age was four times his son age then.find their present ages. \n" ); document.write( "
Algebra.Com's Answer #497758 by balthazar612(14)![]() ![]() ![]() You can put this solution on YOUR website! (x + 4) = 3(y + 4) \n" ); document.write( "(x - 6) = 7(y - 6) \n" ); document.write( "--- \n" ); document.write( "x + 4 = 3y + 12 \n" ); document.write( "x - 6 = 7y - 42 --- \n" ); document.write( "put the system of linear equations into standard form \n" ); document.write( "--- \n" ); document.write( "x - 3y = 8 \n" ); document.write( "x - 7y = -36 \n" ); document.write( "Subtracting equati0n 2 from 1 \n" ); document.write( "4y = 44 Y = 11 \n" ); document.write( "Putting value of y in equation 1 we \n" ); document.write( "get \n" ); document.write( "X-3(11) =8 \n" ); document.write( "X -33 =8 \n" ); document.write( "X= 8+33 X= 41 \n" ); document.write( "answer: \n" ); document.write( "x= father = 41 \n" ); document.write( "y= son = 11 \n" ); document.write( " |