document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825829>Question 825829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves town traveling at 50 miles per hour. Two hours later, a second car, traveling 70 miles per hour, leaves along the same route as the first car. How long would it take for the second car to overtake the first car? \r<BR>\n" );
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document.write( "I have tried to set up my rate distance time table but it just doesn't seem to be working for me. thank you very much for the help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497724 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car A --------------- 50mph\r<BR>\n" );
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document.write( "Car B -----------70 mph\r<BR>\n" );
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document.write( "The distance traveled by both is same when they meet<BR>\n" );
document.write( "but Car A takes 2 hours more\r<BR>\n" );
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document.write( "Time car B = Time Car A +2<BR>\n" );
document.write( "t=d/r\r<BR>\n" );
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document.write( "x/70 =x/50 -2\r<BR>\n" );
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document.write( "x/50 -x/70 =2\r<BR>\n" );
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document.write( "70x-50x= 2*50*70\r<BR>\n" );
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document.write( "20x=2*50*70\r<BR>\n" );
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document.write( "x= 2*50*70/20\r<BR>\n" );
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document.write( "x=50*7\r<BR>\n" );
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document.write( "x=350 miles\r<BR>\n" );
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document.write( "speed of Car B = 70 mph<BR>\n" );
document.write( "distance = 350 miles\r<BR>\n" );
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document.write( "t= 350/70 <BR>\n" );
document.write( "t=5 hours\r<BR>\n" );
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document.write( "car B takes 5 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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