document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69847>Question 69847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can i use pascals triangle and permutations and combinations together or separately to help me complete (a+b)^n were a and b are constant values and n is any power. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49772 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a complete discussion see, \"Mathworld Pascal Triangle\"<BR>\n" );
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document.write( "Briefly the numbers in the nth row of Pascal's triangle are the <BR>\n" );
document.write( "coefficients of (a+b)^(n-1)<BR>\n" );
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document.write( "Ex: (a+b)^3 = 3C3a^3b^0 + 3C2a^2b +3C1ab^2 +3C0a^0b^3<BR>\n" );
document.write( "Those coefficients are 1...3...3...1<BR>\n" );
document.write( "and they are the numbers is the 4th row of Pascal's triangle.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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