document.write( "Question 825913: Ellis is one year younger than Denden. One-half of Ellis' age is three less than two-thirds of Denden's age. What are their present ages?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #497705 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let e = E's age
\n" ); document.write( "Let d = D's age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement
\n" ); document.write( "\"Ellis is one year younger than Denden.\"
\n" ); document.write( "e = d-1
\n" ); document.write( ":
\n" ); document.write( "\" One-half of Ellis' age is three less than two-thirds of Denden's age.\"
\n" ); document.write( " $\"1%2F2\"$ e = $\"2%2F3\"$ d - 3
\n" ); document.write( "Get rid of those annoying denominators, mult by 6, resulting in:
\n" ); document.write( "3e = 4d - 18
\n" ); document.write( "Replace e with (d-1)
\n" ); document.write( "3(d-1) = 4d - 18
\n" ); document.write( "3d - 3 = 4d - 18
\n" ); document.write( "-3 + 18 = 4d - 3d
\n" ); document.write( "15 = d
\n" ); document.write( "D is 15 yrs old
\n" ); document.write( "Find E
\n" ); document.write( "e = 15 - 1
\n" ); document.write( "e = 14 yrs old
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"One-half of Ellis' age is three less than two-thirds of Denden's age.
\n" ); document.write( " $\"1%2F2\"$ (14) = $\"2%2F3\"$ (15) - 3
\n" ); document.write( "7 = 10 - 3 \n" ); document.write( "

\n" );