document.write( "Question 825910: Maridol is twice as old as Maricel. In six years, she will be four times as old as Maricel was three years ago. What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #497685 by Seutip(231)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "x - be Maricel's age in the present \n" ); document.write( "2x - be Maridol's age in present\r \n" ); document.write( "\n" ); document.write( "x-3 - Maricel's age 3 years ago \n" ); document.write( "2x+6 - Maridol's age in 6 years\r \n" ); document.write( "\n" ); document.write( "2x+6 = 4(x-3) \n" ); document.write( "2x+6 = 4x-12 \n" ); document.write( "18 = 2x \n" ); document.write( "9 = x\r \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( "Maricel is 9 years old and Maridol is 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hope that helps, :)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |