document.write( "Question 825910: Maridol is twice as old as Maricel. In six years, she will be four times as old as Maricel was three years ago. What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #497685 by Seutip(231)\"\" \"About 
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Let
\n" ); document.write( "x - be Maricel's age in the present
\n" ); document.write( "2x - be Maridol's age in present\r
\n" ); document.write( "\n" ); document.write( "x-3 - Maricel's age 3 years ago
\n" ); document.write( "2x+6 - Maridol's age in 6 years\r
\n" ); document.write( "\n" ); document.write( "2x+6 = 4(x-3)
\n" ); document.write( "2x+6 = 4x-12
\n" ); document.write( "18 = 2x
\n" ); document.write( "9 = x\r
\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "Maricel is 9 years old and Maridol is 18\r
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\n" ); document.write( "\n" ); document.write( "hope that helps, :)\r
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