document.write( "Question 825886: when p is decreased by 36 the result is 8 less than one-third of p. find p. can u please help me \n" ); document.write( "
Algebra.Com's Answer #497674 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "when \"p\" is decreased by \"36\", we write it as \"p-36\"\r
\n" ); document.write( "\n" ); document.write( "if the result is \"8\" less than \"one-third\" of \"p\". then we write it as \"p%2F3-8\"\r
\n" ); document.write( "\n" ); document.write( "find \"p\": \r
\n" ); document.write( "\n" ); document.write( "\"p-36=p%2F3-8\"...............solve for \"p\", first both sides multiply by \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"3p-3%2A36=3p%2F3-3%2A8\"\r
\n" ); document.write( "\n" ); document.write( "\"3p-108=p-24\"\r
\n" ); document.write( "\n" ); document.write( "\"3p-p=p-24%2B108\"\r
\n" ); document.write( "\n" ); document.write( "\"2p=84\"\r
\n" ); document.write( "\n" ); document.write( "\"p=84%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"p=42\"\r
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