document.write( "Question 825784: please can you help mw with this question:
\n" ); document.write( "a ball is dropped from a tall building and falls from acceleration of magnitude
\n" ); document.write( "10ms-2. the distance between floors in the block is constant. the ball take 0.5s to fall from the 14th to the 13th floor and 0.3 s to fall from the 13th floor to the 13th. what is the distance between floors?
\n" ); document.write( "thankyou
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Algebra.Com's Answer #497662 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"d\"= constant distance between floors, in meters
\n" ); document.write( "\"g=10m\"\"%22%2F%22\"\"s%5E2\"= acceleration of gravity
\n" ); document.write( "\"v\"= downward velocity as the ball reaches the 14th floor, in m/s
\n" ); document.write( "Then, 0.5 seconds later, we have
\n" ); document.write( "\"v%2B10%2A0.5=v%2B5\"= downward velocity as the ball reaches the 13th floor.
\n" ); document.write( "After another 0.3 seconds,
\n" ); document.write( "\"v%2B10%2A0.5%2B10%2A0.3=v%2B8\"= downward velocity as the ball reaches the 12th floor.
\n" ); document.write( "In linear motion with constant acceleration, distance is the product of average speed and time.
\n" ); document.write( "Between the 14th and 13th floors:
\n" ); document.write( "\"%28%28v%2B%28v%2B5%29%29%2F2%29%2A0.5=d\"
\n" ); document.write( "\"%282v%2B5%29%2F2=2d\"
\n" ); document.write( "\"highlight%282v%2B5=4d%29\"
\n" ); document.write( "Between the 13th and 12th floors:
\n" ); document.write( "\"%28%28v%2B8%29%2B%28v%2B5%29%29%2F2%29%2A0.3=d\"
\n" ); document.write( "\"%28%28v%2B8%29%2B%28v%2B5%29%29%2F2%29%2A3=10d\"
\n" ); document.write( "\"%28%28v%2B8%29%2B%28v%2B5%29%29%2A3=20d\"
\n" ); document.write( "\"%282v%2B13%29%2A3=20d\"
\n" ); document.write( "\"highlight%286v%2B39=20d%29\"
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\n" ); document.write( "We solve the system below any way we can
\n" ); document.write( "\"system%282v%2B5=4d%2C6v%2B39=20d%29\" --> \"system%28v=3.5%2Chighlight%28d=3%29%29\" to find that the distance between floor is \"highlight%283%29\"meters.
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\n" ); document.write( "I would use a combination of equations:
\n" ); document.write( "\"2v%2B5=4d\"-->\"3%282v%2B5%29=3%2A%284d%29\"-->\"6v%2B15=12d\"
\n" ); document.write( "\"6v%2B39=20d\"
\n" ); document.write( "-
\n" ); document.write( "\"6v%2B15=12d\"
\n" ); document.write( "-----------
\n" ); document.write( "\"24=8d\" --> \"24%2F8=d\" --> \"highlight%28d=3%29\"
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