document.write( "Question 69843: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #49766 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! $x+$y=$18,000 \n" ); document.write( "or x+(18,000-x)=18,000 \n" ); document.write( ". \n" ); document.write( ".03x+.05(18,000-x)=660 because: \n" ); document.write( "$x invested at 3% + $y invested at 5%=A total of $660 in interest.\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Simplify \n" ); document.write( ".03x+.05(18,000-x)=660 \n" ); document.write( ".03x+900-.05x=660 \n" ); document.write( ".03x+900-900-.05x=660-900 \n" ); document.write( ".03x-.05x=-240 \n" ); document.write( "-.02=-240 \n" ); document.write( "-.02x/-.02=-240/-.02 \n" ); document.write( "x=12,000 \n" ); document.write( ". \n" ); document.write( "Plugging x=$12,000 back into the original equation: \n" ); document.write( ".03x+.05(18,000-x)=660 \n" ); document.write( ".03(12,000)+.05(18,000-12,000)=660 \n" ); document.write( "360+ .05(6,000)=660 \n" ); document.write( "360+300=660 \n" ); document.write( "660=660 checks out \n" ); document.write( " |