document.write( "Question 69843: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #49766 by tutorcecilia(2152)\"\" \"About 
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$x+$y=$18,000
\n" ); document.write( "or x+(18,000-x)=18,000
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\n" ); document.write( ".03x+.05(18,000-x)=660 because:
\n" ); document.write( "$x invested at 3% + $y invested at 5%=A total of $660 in interest.\r
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\n" ); document.write( "Simplify
\n" ); document.write( ".03x+.05(18,000-x)=660
\n" ); document.write( ".03x+900-.05x=660
\n" ); document.write( ".03x+900-900-.05x=660-900
\n" ); document.write( ".03x-.05x=-240
\n" ); document.write( "-.02=-240
\n" ); document.write( "-.02x/-.02=-240/-.02
\n" ); document.write( "x=12,000
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\n" ); document.write( "Plugging x=$12,000 back into the original equation:
\n" ); document.write( ".03x+.05(18,000-x)=660
\n" ); document.write( ".03(12,000)+.05(18,000-12,000)=660
\n" ); document.write( "360+ .05(6,000)=660
\n" ); document.write( "360+300=660
\n" ); document.write( "660=660 checks out
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