document.write( "Question 825816: If cos(theta)=4/5, 0<(theta)\n" ); document.write( "find the exact value of
\n" ); document.write( "a) Sin 2(theta)
\n" ); document.write( "b) Sin 4(theta)
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Algebra.Com's Answer #497645 by lwsshak3(11628)\"\" \"About 
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If cos(theta)=4/5, 0<(theta) find the exact value of
\n" ); document.write( "a) Sin 2(theta)
\n" ); document.write( "b) Sin 4(theta)
\n" ); document.write( "***
\n" ); document.write( "cosx=4/5 (working with a (3-4-5) reference right triangle)
\n" ); document.write( "sinx=3/4
\n" ); document.write( "..
\n" ); document.write( "a)sin2x=2sinxcosx=2*4/5*3/5=24/25
\n" ); document.write( "cos2x=√(1-sin^2(2x))=√(1-(576/625))=√(1-(576/625))=√(49/625)=7/25
\n" ); document.write( "..
\n" ); document.write( "b)sin4x=2sin2xcos2x=2*24/25*7/25=336/625
\n" ); document.write( "..
\n" ); document.write( "calculator check:
\n" ); document.write( "cosx=4/5
\n" ); document.write( "x≈36.87˚
\n" ); document.write( "4x≈147.48˚
\n" ); document.write( "sin4x≈sin(147.48˚)≈0.5376..
\n" ); document.write( "exact value as calculated=336/625≈0.5376..
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