document.write( "Question 69843: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #49764 by checkley75(3666)\"\" \"About 
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.05X+.03(18000-X)=660
\n" ); document.write( ".05X+540-.03X=660
\n" ); document.write( ".02X=660-540
\n" ); document.write( ".02X=120
\n" ); document.write( "X=120/.02
\n" ); document.write( "X=6000 INVESTED AT 5% THUS
\n" ); document.write( "18000-6000=12000 INVESTED AT 3%
\n" ); document.write( "PROOF
\n" ); document.write( ".05*6000+.03*12000=660
\n" ); document.write( "300+360=660
\n" ); document.write( "660=660
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