document.write( "Question 9897: Arctan(1) + Arcsin(0) + Arccos\"%28sqrt%283%29%2F2%29\" \n" ); document.write( "
Algebra.Com's Answer #497638 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Arctan(1) + Arcsin(0) + Arccos\"%28sqrt%283%29%2F2%29\"\r\n" );
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document.write( "Arctan(1) = ? asks tan(?) = 1 ---> answer: 45° or \"pi%2F4\" radians\r\n" );
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document.write( "Arcsin(0) = ? asks sin(?) = 0 ---> answer: 0°  or 0 radians\r\n" );
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document.write( "Arccos\"%28sqrt%283%29%2F2%29\" = ? asks cos(?) = \"sqrt%283%29%2F2\" ---> answer: 30° or \"pi%2F6\" radians\r\n" );
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document.write( "So, if your answer is to be in degrees:\r\n" );
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document.write( "Arctan(1) + Arcsin(0) + Arccos\"%28sqrt%283%29%2F2%29\" = 45° + 0° + 30° = 75°    \r\n" );
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document.write( "Or if your answer is to be in radians:\r\n" );
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document.write( "Arctan(1) + Arcsin(0) + Arccos\"%28sqrt%283%29%2F2%29\" = \"pi%2F4\" + \"%220%22\" + \"pi%2F6\" = \"pi%2F4\" + \"pi%2F6\" = \"3pi%2F12\" + \"2pi%2F12\" = \"5pi%2F12\"\r\n" );
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document.write( "Edwin
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