document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825846>Question 825846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular ping pong table is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=45+feet%5E2 ALIGN=MIDDLE  ALT=\"45+feet%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. The length is 4 feet longer than the width. Let x = the width. Find the length in feet.\r<BR>\n" );
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document.write( "So far I have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=45x%5E2%2B4x=0 ALIGN=MIDDLE  ALT=\"45x%5E2%2B4x=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497632 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is length*width<BR>\n" );
document.write( "Given: width = x, length, l = x+4<BR>\n" );
document.write( "The area = x*(x+4) = 45<BR>\n" );
document.write( "x^2+4x-45 = 0<BR>\n" );
document.write( "This can be factored as (x-5)(x+9) = 0<BR>\n" );
document.write( "Taking the positive solution, we have x = 5<BR>\n" );
document.write( "Therefore, the length = 5+4 = 9 ft. </SPAN>\n" );
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