document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69848>Question 69848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 120 milliliters of a 59% solution but has only 32% and 68% solutions available. Find how many milliliters of each that should be mixed to get the disired solution.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49762 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 120*.59=.32X+.68(120-X)<BR>\n" );
document.write( "70.8=.32X+81.6-.68X<BR>\n" );
document.write( ".68X-.32X=81.6-70.8<BR>\n" );
document.write( ".36X=10.8<BR>\n" );
document.write( "X=10.8/.36<BR>\n" );
document.write( "X=30 MILLILETERS OF 32% SOLUTION &<BR>\n" );
document.write( "120-30=90 MILLILETERS OF 68% SOLUTION<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "70.8=.32*30+.68*61.2<BR>\n" );
document.write( "70.8=9.6+61.2<BR>\n" );
document.write( "70.8=70.8 </SPAN>\n" );
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