document.write( "Question 69850: I am having a hard time figuring out how to write the equation for this problem:\r
\n" ); document.write( "\n" ); document.write( "Joyce makes $6000 more per year than her husband does. Joyce saves 10% of her income for retirement and her husband saves 6%. If altogether they save $5400 per year, then how much does each of them earn per year?
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Algebra.Com's Answer #49760 by checkley75(3666)\"\" \"About 
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Joyce's salary=x+6000
\n" ); document.write( "Husband's salary=x
\n" ); document.write( "10% of Joyce's salary plus 6% of her husband's salary which equals 5400.
\n" ); document.write( ".1(x+6000)+.06x=5400
\n" ); document.write( ".1x+600+.06x=5400
\n" ); document.write( ".16x=5400-600
\n" ); document.write( ".16x=4800
\n" ); document.write( "x=4800/.16
\n" ); document.write( "x=30000 which is hubby's salary.
\n" ); document.write( "thus Joyces salary is 30000+6000=36000
\n" ); document.write( "proof
\n" ); document.write( ".1*36000+.06*30000=5400
\n" ); document.write( "3600+1800=5400
\n" ); document.write( "5400=5400
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