document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825534>Question 825534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pq(p-3)+p for p=5,q=2,r=-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497598 by </B><A HREF=/tutors/aboutme.mpl?userid=sarcasticpie><B>sarcasticpie(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarcasticpie><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sarcasticpie><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi :) I understand that p = 5, q = 2 and r = -5\r<BR>\n" );
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document.write( "pq (p-3) + p\r<BR>\n" );
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document.write( "Using substitution:\r<BR>\n" );
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document.write( "= [(5)(2)](5 - 3) + 5<BR>\n" );
document.write( "= (10)(2) + 5<BR>\n" );
document.write( "= 20 + 5<BR>\n" );
document.write( "= 25\r<BR>\n" );
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document.write( "Hope it helps :) x </SPAN>\n" );
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